4CH1

States of Matter

Principles of Chemistry

Exam Frequency Analysis

Past paper frequency (2018 to 2024)

This topic accounts for approximately 6% of your exam marks.

stable
Low
Stable6%

Appears regularly as short-answer questions on particle diagrams and state changes.

Aim

  • Determine the solubility (g per 100 g water) of a soluble salt, typically copper(II) sulfate or potassium nitrate, at a stated temperature

Apparatus

  • Evaporating basin
  • Boiling tube
  • Water bath (a heated beaker of water will substitute)
  • Thermometer
  • Balance reading to 0.01 g
  • Bunsen burner, tripod, gauze
  • Stirring rod
  • The chosen soluble solid

Method

  1. Weigh the empty evaporating basin; record its mass
  2. Half-fill a boiling tube with water and warm it in the water bath to just above the target temperature (say, just above 30 °C)
  3. Add the chosen solid in small portions, stirring after each addition, until further additions stop dissolving and a small amount of solid residue settles on the base of the tube
  4. Cool the boiling tube to exactly the target temperature (30 °C), stirring gently; let the residue settle
  5. Decant the clear saturated solution into the pre-weighed basin (leaving the residue behind in the tube); reweigh the basin
  6. Heat the basin gently to evaporate the water; reduce the heat before the basin runs dry, to prevent spitting
  7. Heat to constant mass: cool, weigh, reheat, cool, reweigh, repeating until two consecutive masses agree
  8. Calculate the solubility from the recorded masses

Sample calculation

ReadingMass / g
Empty basin30.00
Basin + saturated solution90.00
Basin + dry solid (constant mass)50.00
  • Mass of solution: 90.00 − 30.00 = 60.00 g
  • Mass of solute: 50.00 − 30.00 = 20.00 g
  • Mass of water: 60.00 − 20.00 = 40.00 g
  • Solubility at 30 °C = (20.00 / 40.00) × 100 = 50.0 g per 100 g of water
  • Mass % of solute in the solution = (20.00 / 60.00) × 100 = 33.3 %

Sources of error

  • Transferring undissolved residue into the basin → overestimates solubility; decant carefully, or filter at the target temperature
  • Loss of solid by spitting during evaporation → heat gently near dryness; finish on residual heat
  • Solution cooling below the target temperature before decanting → solubility falls; less solid in the decanted liquid; decant promptly
  • Incomplete drying → trapped water inflates the apparent solute mass; always heat to constant mass