This topic accounts for approximately 9% of your exam marks.
stable
Medium
Stable9%
Ion formation, lattice structures and properties of ionic compounds tested consistently.
An ionic compound is electrically neutral overall. The total positive charge from the cations exactly cancels the total negative charge from the anions
Two equivalent methods for working out the formula: direct comparison and swap-and-drop
Direct comparison
Pick the smallest whole-number ratio of cations to anions that makes the total charge balance to zero
Iron(II) sulfate: Fe²⁺ has +2, SO₄²⁻ has −2; (+2) + (−2) = 0, so 1 Fe²⁺ pairs with 1 SO₄²⁻
Formula: FeSO₄
Swap-and-drop
Faster when the cation and anion have different charge sizes
Procedure:
Write the two ions side by side, with their charge numbers as superscripts
Swap each ion's charge size to become the subscript of the other ion
Drop the +/− signs; drop any subscript of 1 (it is always implied)
Simplify the subscripts if they share a common factor
Examples:
Copper(II) chloride: Cu²⁺ and Cl⁻ → swap gives Cu₁Cl₂ → drop the 1 → CuCl₂