Mg is the reducing agent (gives away electrons); Cu2+ is the oxidising agent (accepts them)
Exam tip
Explaining why a displacement reaction is redox (two marks)
What comes up: a two-mark question asks you to explain why a metal displacement reaction (for example, aluminium reducing iron oxide) is a redox reaction.
Write (two marks): (1) one substance gains oxygen (or loses electrons) and is oxidised — state which one. (2) the other substance loses oxygen (or gains electrons) and is reduced — state which one. For example: aluminium gains oxygen and is oxidised; iron(III) oxide loses oxygen and is reduced.
Watch out: the mark scheme rejects "iron loses oxygen" as the description of what is reduced — it is iron(III) oxide (the compound) that loses oxygen, not iron itself. Name the compound, not the metal element.
Spectator ions and ionic equations
In the full equation Mg(s) + CuSO4(aq) → MgSO4(aq) + Cu(s), the sulfate ion SO42− appears on both sides unchanged
An ion that is unchanged in a reaction is a spectator ion — it does not take part in the chemistry
Leaving out the spectator ions gives the , which highlights the actual redox change: Mg(s) + Cu2+(aq) → Mg2+(aq) + Cu(s)
A practice prompt
In the reaction Cu(s) + 2 AgNO3(aq) → Cu(NO3)2(aq) + 2 Ag(s), Cu loses two electrons to form Cu2+ (oxidation) while each Ag+ gains one electron to form Ag (reduction)
Copper is therefore the reducing agent here, and silver(I) is the oxidising agent