Principle
- A reactive material is sealed inside a fixed volume of air and allowed to combine with the oxygen in that air
- The reacted oxygen leaves the gas phase, so the trapped gas volume shrinks
- The change in volume, divided by the starting volume, gives the percentage of oxygen
Method: iron in a burette
- Push damp iron wool into the closed lower end of an inverted burette, so the iron has plenty of contact with water and air
- Stand the burette mouth-down in a trough of water, with the tap closed at the top
- Read the water level inside the burette against the scale and write it down as the initial reading
- Leave the apparatus for several days while the iron slowly rusts, using up oxygen from the trapped air
- Once the water level stops rising, take a second reading against the same scale
Sample calculation (worked through)
- Suppose the trapped air column measured 45.0 cm3 at the start, and 36.0 cm3 once rusting had stopped
- The volume of oxygen used up = 45.0 − 36.0 = 9.0 cm3
- Percentage of O2 in the original air = (9.0 ÷ 45.0) × 100 = 20.0%
- This is close to the accepted value near 21%; the small shortfall is because rusting is slow and some oxygen may remain unreacted
Alternative material: burning phosphorus
- Phosphorus burns readily in a sealed bell jar over water, consuming oxygen quickly rather than over days
- The water rises into the jar as the trapped gas contracts, by the same volume principle
- Phosphorus is toxic, so the iron-wool method is normally preferred for school work
Calculating the percentage of oxygen — avoiding the one-mark trap
What comes up: you are given a starting volume of air and the volume remaining after all the oxygen has reacted. You must calculate the percentage of oxygen.
Write (two marks): (1) Subtract the final volume from the starting volume to find the volume of oxygen consumed. (2) Divide that oxygen volume by the starting volume (not the remaining volume) and multiply by 100.
Watch out: dividing the oxygen volume by the remaining gas volume rather than the starting volume is the most common slip. The mark scheme awards only 1 out of 2 marks for that error, even if your subtraction was correct.