4PH1

Forces, Movement & Changing Shape

Forces & Motion · 1 question type

Exam Frequency Analysis

Past paper frequency (2018 to 2024)

This topic accounts for approximately 14% of your exam marks.

stable
High
Stable14%

F = ma, resultant forces and Hooke's Law calculations are high-frequency multi-mark questions.

Balanced forces

  • The forces on an object are balanced when they add up to a zero resultant
  • A balanced object either stays still or carries on at a constant in a straight line, because its motion does not change at all
  • Example: a book at rest on a desk feels a downward weight and an equal upward reaction force from the desk. The two cancel out

Unbalanced forces and Newton's second law

  • The forces are unbalanced when they do not add to zero, so there is a non-zero resultant
  • A non-zero resultant force makes the object accelerate: it can speed up, slow down, or change direction
  • The size of the acceleration is given by Newton's second law of motion:

F = m × a

  • where:
    • F = resultant force (N)
    • m = mass (kg)
    • a = acceleration (m/s²)
  • Rearranges to a = F / m and m = F / a

Example A — a delivery lorry of mass 1200 kg accelerates uniformly from rest to 18 m/s in 6.0 s. Calculate (i) the acceleration and (ii) the resultant force driving the lorry forward.

  • (i) a = (v − u) / t = (18 − 0) / 6.0 = 3.0 m/s²
  • (ii) F = m × a = 1200 × 3.0 = 3600 N

Example B — a cyclist plus bicycle have a combined mass of 85 kg. They brake from 12 m/s to a halt in 4.0 s. Calculate the size of the braking force.

  • a = (v − u) / t = (0 − 12) / 4.0 = −3.0 m/s²
  • F = m × a = 85 × (−3.0) = −255 N
  • The negative sign tells you the resultant force points opposite to the motion, i.e. it is the brakes pushing backwards against the cyclist's forward travel
Worked example

F = ma with a unit-conversion step

A resultant force of 6 N acts on a mass of 200 g. Calculate the acceleration.

Solution:

  • Convert the mass to kilograms first: 200 g = 200 ÷ 1000 = 0.20 kg
  • Rearrange F = m × a to make a the subject: a = F ÷ m
  • Substitute and evaluate: a = 6 ÷ 0.20 = 30 m/s²

Always convert grams to kilograms before substituting — leaving the mass as 200 g gives a = 0.03 m/s², a power-of-ten error the mark scheme penalises. Show the substituted formula, not just "F = m × a" on its own.