What happens
- In the presence of ultraviolet (UV) light, an alkane reacts with a halogen (chlorine or bromine) by a substitution reaction
- A hydrogen atom on the alkane is swapped for a halogen atom; the displaced hydrogen leaves as a hydrogen halide (HCl or HBr)
- General word equation:
alkane + halogen → halogenoalkane + hydrogen halide
- UV light is needed to break the halogen–halogen bond and start the reaction; the reaction does not occur in the dark
Example — ethane and bromine
- Ethane reacts with bromine in UV light to give bromoethane and hydrogen bromide:
C2H6(g) + Br2(g) → C2H5Br(g) + HBr(g)
ethane + bromine → bromoethane + hydrogen bromide
- Visible clue: the orange-brown bromine vapour fades as the reaction proceeds and the bromine is consumed
Example — ethane and chlorine
- Ethane reacts with chlorine in UV light to give chloroethane and hydrogen chloride:
C2H6(g) + Cl2(g) → C2H5Cl(g) + HCl(g)
- The same pattern: one H atom on the ethane swaps with one Cl atom from the chlorine, releasing HCl
Products: halogenoalkanes
- The organic product of an alkane–halogen substitution is called a halogenoalkane (or haloalkane) — an alkane with one (or more) hydrogen atoms replaced by halogen atoms
- Naming follows the same stem-plus-ending rule as the parent alkane, but the halogen is named as a prefix:
- Methane + Cl2 → chloromethane (CH3Cl)
- Ethane + Br2 → bromoethane (C2H5Br)
- Propane + I2 → iodopropane (C3H7I)
- If more than one halogen has been substituted, prefixes like di-, tri- and a position number show how many and where (for example, 1,2-dichloroethane has one Cl on each of its two carbons)
Why this reaction matters
- Halogenoalkanes are useful as solvents, refrigerants, propellants and starting materials for pharmaceuticals
- A historically important sub-family was the chlorofluorocarbons (CFCs), once used in fridges and aerosol propellants
- CFCs were phased out under the Montreal Protocol because they migrate to the upper atmosphere and damage the ozone layer