Force as the rate of change of momentum
- Combining F = ma and the definition p = mv gives a more general form of Newton's second law:
F = Δp / t = (mv − mu) / t
- where:
- F = resultant force (N)
- mv − mu = change in momentum, Δp (kg m/s), i.e. final momentum minus initial momentum
- t = time over which the change happens (s)
- In words: the resultant force on an object equals its rate of change of momentum
Contact time and impact force
- For a given change in momentum, the force and the contact time are inversely proportional to one another:
- Halve the contact time and the impact force doubles
- Triple the contact time and the impact force falls to a third
- Real safety design therefore aims to extend the contact time during a collision to make the impact force as small as possible (see section 5)
Example A — during the same return shot, a 0.40 kg football undergoes the same change in momentum of 8.0 kg m/s in two different scenarios: scenario 1 has a foot-on-ball contact time of 0.050 s, scenario 2 has a contact time of 0.50 s. Compare the average force on the ball.
- Scenario 1: F = Δp / t = 8.0 / 0.050 = 160 N
- Scenario 2: F = Δp / t = 8.0 / 0.50 = 16 N
- The same change in momentum, delivered over ten times longer, gives a force that is ten times smaller
Example B — a 1200 kg car drives at 18 m/s into a wall and rebounds at 4.0 m/s in the opposite direction. The collision lasts 0.20 s. Calculate the average force on the car and state its direction.
- Take the car's forward (towards-wall) direction as positive: u = +18 m/s, v = −4.0 m/s
- Δp = m(v − u) = 1200 × (−4.0 − 18) = 1200 × (−22) = −26 400 kg m/s
- F = Δp / t = −26 400 / 0.20 = −132 000 N
- The minus sign tells you the force on the car points in the opposite direction to its original motion, that is, backwards from the wall, as you would expect