Properties of Radiation
Radioactivity & Particles · 2 question types
Exam Frequency Analysis
Past paper frequency (2018 to 2024)
This topic accounts for approximately 8% of your exam marks.
Properties of alpha, beta and gamma radiation and nuclear equations tested consistently.
Alpha decay
- In alpha decay, the nucleus emits an alpha particle (a helium-4 nucleus)
- Effects on the parent nucleus:
- decreases by 4
- decreases by 2
- A new element is formed (since Z has changed)
- General equation:
ᴬ_Z X → ᴬ⁻⁴_Z₋₂ Y + ⁴₂α
Beta decay
- In beta decay, a neutron inside the nucleus transforms into a proton plus an electron. The electron is ejected as the beta particle; the proton stays in the nucleus
- Effects on the parent nucleus:
- Mass number stays the same (a neutron has become a proton, but the total nucleon count is unchanged)
- Atomic number increases by 1 (one more proton)
- A new element is formed
- General equation:
ᴬ_Z X → ᴬ_Z₊₁ Y + ⁰₋₁β
Gamma decay
- In gamma decay, the nucleus emits a burst of high-energy electromagnetic radiation (a gamma photon)
- Effects on the parent nucleus:
- Mass number stays the same
- Atomic number stays the same
- No new element is formed; the nucleus has simply lost some energy
- Gamma emission often happens immediately after another decay (alpha or beta) leaves the daughter nucleus in an excited state. The excited nucleus then sheds the excess energy as a gamma photon
- General equation:
ᴬ_Z X → ᴬ_Z X + ⁰₀γ
Neutron emission
- A handful of very neutron-rich isotopes can decay by ejecting a single directly
- Effects on the parent nucleus:
- Mass number decreases by 1 (one nucleon has gone)
- Atomic number stays the same (no protons lost)
- The result is a different of the same element
- General equation:
ᴬ_Z X → ᴬ⁻¹_Z X + ¹₀n
Balancing nuclear equations
- Two simple rules let you check or complete any decay equation:
- The sum of mass numbers on the left must equal the sum on the right
- The sum of atomic numbers on the left must equal the sum on the right
- A balanced equation conserves both mass and charge across the reaction
Completing an alpha decay equation
A nucleus of radon-220 (atomic number 86) undergoes alpha decay to form a polonium nucleus. Complete the nuclear equation by finding the missing mass number and atomic number of the daughter nucleus and the alpha particle.
Solution:
- An alpha particle has mass number 4 and atomic number 2, written ⁴₂α.
- Mass number check: 220 = daughter mass number + 4, so daughter mass number = 216.
- Atomic number check: 86 = daughter atomic number + 2, so daughter atomic number = 84.
- Element with Z = 84 is polonium (Po).
- Completed equation: ²²⁰₈₆Rn → ²¹⁶₈₄Po + ⁴₂α
Completing a beta decay equation
What comes up: given an incomplete nuclear equation for beta decay with blank boxes for the mass or atomic numbers, fill in the missing values.
Write (two marks): (1) The mass number stays the same (a neutron converts to a proton, so total nucleons are unchanged). (2) The atomic number increases by 1 (one extra proton in the nucleus), so identify the new element at Z + 1.
Watch out: a common slip is decreasing the atomic number or changing the mass number. In beta decay a neutron becomes a proton — the nucleon count is unchanged and the proton count goes up by one. The beta particle itself carries mass number 0 and atomic number −1 (written ⁰₋₁β).