MathematicsExam code: 0580

Transformations

Vectors and Transformations

Doing one

  • An enlargement resizes the shape by a scale factor from a fixed centre of enlargement
  • Each vertex moves along the line from the centre through it, ending scale-factor times as far from the centre
  • Multiply each distance from the centre, both across and up, by the scale factor
Shape C enlarged to C prime with the centre of enlargement marked at (2, 1): a red ray is drawn from the centre through a vertex of C and on to the matching vertex of C prime, which sits twice as far along it
Source: Enlargements by Save My Exams
  • A scale factor between 0 and 1 makes the image smaller, even though it is still called an enlargement
A large shape enlarged by a fraction to a much smaller green image: the rays from the centre of enlargement at (4, 2) run from each vertex of the object inwards, and the image sits between the object and the centre
Source: Enlargements by Save My Exams
  • A negative scale factor throws the image across to the far side of the centre and inverts it, so it acts as a 180° rotation as well as a resize
Triangle A enlarged with scale factor −2 about the centre marked with a cross at (1, 2): rays run from each vertex of A through the centre and out the other side, so the image B is twice as large, upside down and on the opposite side of the centre
  • Every length multiplies by the scale factor, so the image is similar to the object rather than congruent

Describing one

  • Say enlargement, then give the scale factor, then the centre as coordinates
  • Find the centre by drawing a line through each pair of corresponding vertices and seeing where they all cross
Working backwards to find a centre of enlargement: a red line is ruled through three pairs of matching vertices of the large shape A and the small shape B, and all of the lines meet at one point, which is the centre
Source: Enlargements by Save My Exams
  • Find the scale factor by dividing an image length by the matching object length

Worked example

Describing an enlargement

Triangle A has vertices (1, 1), (3, 1) and (1, 2). Triangle B has vertices (2, 2), (6, 2) and (2, 4). Describe fully the single transformation that maps A onto B.

A coordinate grid with x from 0 to 7 and y from 0 to 5. Triangle A is drawn with vertices at (1, 1), (3, 1) and (1, 2), and the larger triangle B with vertices at (2, 2), (6, 2) and (2, 4). No centre of enlargement and no rays are drawn.

Solution:

  • B is bigger than A, so the only candidate is an enlargement: the other three keep the size the same
  • Compare a pair of matching sides: A has a base from (1, 1) to (3, 1), which is 2 units, and B has a base from (2, 2) to (6, 2), which is 4 units
  • Scale factor = 4 ÷ 2 = 2
  • Draw a line through (1, 1) and (2, 2), another through (3, 1) and (6, 2), and a third through (1, 2) and (2, 4)
  • All three meet at the origin, so that is the centre
  • The full description is an enlargement, scale factor 2, centre (0, 0)
  • Check: each vertex of B is exactly twice as far from the origin as the matching vertex of A

Exam tip

One transformation, every property

Name exactly one transformation, in its proper word: rotation, not turn or spin; enlargement, not dilation or reduction. Naming two scores nothing for the whole part, so a negative scale factor is one enlargement, never a rotation plus an enlargement. The name and each property (angle with direction, centre, scale factor, vector) earn a mark each, so write every one even when unsure of one. Describing a single transformation is set in 11 of the 21 papers.

Worked example

An enlargement with a negative scale factor

Triangle A has vertices (−1, 2), (−3, 2) and (−1, 6). Triangle B has vertices (5, −1), (6, −1) and (5, −3). Describe fully the single transformation that maps A onto B.

A coordinate grid with x from −4 to 7 and y from −4 to 7. Triangle A is drawn with vertices at (−1, 2), (−3, 2) and (−1, 6), and the smaller triangle B with vertices at (5, −1), (6, −1) and (5, −3). No centre of enlargement and no rays are drawn.

Solution:

  • B is smaller than A, so this is an enlargement, the only one of the four transformations that changes size
  • Compare matching sides: A's vertical side from (−1, 2) to (−1, 6) is 4 units, and B's from (5, −1) to (5, −3) is 2 units, so the size factor is 2 ÷ 4 = ½
  • B is upside down: from the right angle, A's sides run up and to the left, while B's run down and to the right, so the image is inverted and the scale factor is negative, −½
  • Join each pair of matching vertices: (−1, 2) to (5, −1), (−3, 2) to (6, −1), and (−1, 6) to (5, −3)
  • The three lines cross at (3, 0), between the two shapes, which is where the centre of a negative enlargement always lies
  • Check from the centre: (−1, 2) is 4 left and 2 up from (3, 0), and −½ of that is 2 right and 1 down, which lands on (5, −1)
  • The full description is an enlargement, scale factor −½, centre (3, 0)

Build on this topic