MathematicsExam code: 0580

Linear Graphs

Coordinate Geometry and Graphs

From an equation

  • Build a small table of values by substituting three x values that are spread across the axes you are given
  • Three points, not two: a slip in one of three points shows up because it misses the line through the other two, whereas two points always look convincing
  • Plot the points and join them with a ruled line that runs the full width of the grid
Two straight lines drawn on the same grid: a steep uphill line through (0, −1) and (1, 2), stepping 1 across and 3 up, and a shallow downhill line through (0, 3) and (5, 0)
Source: Drawing linear graphs by Save My Exams
  • Alternatively start at (0, c) and step out the gradient, going one right and m up each time, down instead if m is negative
  • For a gradient written as a fraction, step across by the bottom number and up by the top number
A shallow uphill line on a grid through (0, −1) and (3, 1), with a dashed triangle showing 3 across against 2 up, giving a gradient of two thirds
Source: Gradient of a line by Save My Exams

From the ax + by = c form

  • A quicker route for this form is to find where the line meets each axis
  • Substitute x = 0 to get the point on the y-axis, then y = 0 to get the point on the x-axis
  • Join those two points and extend the line across the grid
    • For 3x + 4y = 24, setting x = 0 gives (0, 6) and setting y = 0 gives (8, 0)

Worked example

Drawing a line two ways

Draw y = 2x + 3 for x from −1 to 2, and draw 3x + 2y = 12.

Solution:

  • For the first, build a short table of values
  • x = −1 gives y = 1; x = 0 gives 3; x = 1 gives 5; x = 2 gives 7
  • Plot (−1, 1), (0, 3), (1, 5) and (2, 7), and join them with a ruled line
  • For the second, the cover-up method is quicker than rearranging
  • Setting x = 0 gives 2y = 12, so y = 6 and the line passes through (0, 6)
  • Setting y = 0 gives 3x = 12, so x = 4 and the line passes through (4, 0)
  • Plot those two intercepts and rule the line through them
  • Two points fix a straight line, but a third is worth plotting as a check
A grid from x = −1 to 5 and y = −2 to 8 with both lines drawn: y = 2x + 3 ruled through the crosses at (−1, 1), (0, 3), (1, 5) and (2, 7), and 3x + 2y = 12 ruled across the grid through the crosses at (0, 6) and (4, 0)

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