0580

Histograms

Statistics

The formula both ways

  • The syllabus gives the definition: frequency density = frequency ÷ class width
  • Rearranged, that gives the reverse reading: frequency = frequency density × class width
  • The class width is the upper bound minus the lower bound of the interval
  • Set the work out in a table with two extra columns, one for the class width and one for the frequency density
  • Write the division in each cell rather than only the answer, since that is what shows the method
Worked example

Frequency densities from a table

The table records the mass m grams of 110 items: 24 with 0 < m ⩽ 20, 35 with 20 < m ⩽ 30, 30 with 30 < m ⩽ 50 and 21 with 50 < m ⩽ 80. Find the frequency density of every class.

Solution:

  • Find each class width first, then divide the frequency by it
Mass (m g)FrequencyClass widthFrequency density
0 < m ⩽ 20242024 ÷ 20 = 1.2
20 < m ⩽ 30351035 ÷ 10 = 3.5
30 < m ⩽ 50302030 ÷ 20 = 1.5
50 < m ⩽ 80213021 ÷ 30 = 0.7
  • Compare the second and third classes: 35 items against 30, almost the same count, yet the second bar is more than twice as tall because those 35 are squeezed into a width of 10 while the 30 are spread across 20