0580
Circle Theorems
Geometry
The angle in a semicircle is 90°
- Where a triangle has the diameter as one side and its third corner on the circumference, the angle at that corner is a right angle
- To spot it, check that one side runs through the centre and that every corner lies on the circumference
- Whichever corner faces the diameter is the one holding the right angle

- It is the special case of the centre theorem, since the straight angle of 180° at the centre halves to 90°
Worked example
Using the semicircle and the triangle
The diameter LN is drawn in a circle, and M is a third point on the circumference. Angle MLN is 28°. Find angle MNL, giving reasons.
Solution:
- LN is a diameter and M lies on the circumference, so angle LMN = 90°
- The reason is that the angle in a semicircle is 90°
- The three angles of triangle LMN add to 180°
- Angle MNL = 180 − 90 − 28 = 62°
- The second reason is that the angles in a triangle add to 180°
A tangent meets a radius at 90°
- A tangent touches the circle at exactly one point, and the radius drawn to that point is perpendicular to it
- Draw the radius in yourself whenever a tangent appears, because the right angle is usually what unlocks the question
- Mark schemes accept "tangent and radius are perpendicular" as well as the ninety-degree form, and allow diameter in place of radius
