4CH1

Rates of Reaction

Physical Chemistry · 3 question types

Exam Frequency Analysis

Past paper frequency (2018 to 2024)

This topic accounts for approximately 8% of your exam marks.

stable
Low
Stable8%

Factors affecting rate and collision theory are high-frequency multi-mark questions.

The collision theory model

  • For two reactant particles to react, they must:
    • Collide with each other
    • Collide with at least the minimum kinetic energy needed to break the existing bonds, called the (Ea)
    • Collide with the correct orientation so that bonds can rearrange
  • A collision that meets all three conditions is a
  • The rate of reaction is set by the number of successful collisions per second
  • Anything that increases either the frequency of collisions or the proportion of collisions that have enough energy will speed the reaction up

How concentration changes the rate

  • A higher concentration packs more reactant particles into the same volume
  • More particles in a fixed volume means more collisions per second between the right kinds of particle
  • More collisions → more successful collisions per second → faster reaction
  • Doubling concentration roughly doubles the collision rate
Exam tip

Explaining concentration and rate using collision theory

What comes up: a 3-mark question asking you to explain, using collision theory, how decreasing (or increasing) concentration affects the rate of reaction.

Write (three marks): (1) Lower concentration means fewer particles in the same volume. (2) There are fewer collisions per unit time between reactant particles. (3) So the rate of reaction decreases.

Watch out: mentioning kinetic energy or particle movement when answering a concentration question. The mark scheme specifically rejects references to kinetic energy or particle speed in this context — energy ideas belong to the temperature explanation, not the concentration one.

How pressure changes the rate (for gases)

  • Increasing the pressure of a gas means compressing the same number of particles into a smaller volume
  • The result is the same as increasing concentration in solution — more particles per unit volume, more collisions per second, faster reaction

How temperature changes the rate

  • Increasing the temperature has two effects, both of which speed the reaction up:
    • Particles move faster and so collide more often
    • More importantly, a larger fraction of particles now have kinetic energy at or above the activation energy, so a much larger proportion of collisions are successful
  • The energy effect dominates: as a quick guide, the rate of many common reactions doubles for every 10 °C rise in temperature
Two reaction vessels of the same reactant particles: on the left, at lower temperature, only some collisions are effective; on the right, after an increase in temperature, the particles collide more often and a greater proportion of collisions are effective
Source: Explaining Rates by Save My Exams
Exam tip

Explaining temperature and rate using collision theory

What comes up: a 3-mark question asking you to explain, in terms of collision theory, how increasing temperature affects the rate of reaction.

Write (three marks): (1) Particles have more (kinetic) energy, so they move faster. (2) A greater proportion of particles now have energy at or above the activation energy. (3) There are more successful collisions per unit time, so the rate increases.

Watch out: saying only "more collisions" — without the energy/activation-energy point — will drop a mark. The mark scheme treats the energy idea as a separate, credited point from the collision frequency idea. Both are needed for full marks.

How surface area changes the rate

  • For a solid reacting with a liquid or gas, the reaction can only happen at the surface of the solid where the two phases meet
  • Cutting the solid into smaller pieces exposes more of the underlying particles
  • More exposed area = more collisions per second between the solid surface and the surrounding particles = faster reaction
  • Same idea as crushing a sugar cube into powder — it dissolves much faster