0580
Surds
Number
Why it is done
- A fraction with a root on the bottom has an irrational denominator
- Rationalising the denominator rewrites it as an equivalent fraction whose denominator is rational
- The numerator may still contain a root; only the denominator has to be cleared
A single root on the bottom
- Multiply numerator and denominator by that root
- This multiplies the fraction by 1, so its value is unchanged, and the denominator becomes a whole number
- 6/√3 becomes 6√3/3, which simplifies to 2√3
A sum or difference on the bottom
- Multiply numerator and denominator by the same expression with the middle sign reversed
- The denominator then expands as a difference of two squares, and both roots vanish
- (a + √b)(a − √b) = a² − b
Worked example
Rationalising a two-term denominator
Rationalise the denominator of 5 ÷ (4 + √2), giving the answer in its simplest form.
Solution:
- Reverse the sign in the denominator and multiply top and bottom by 4 − √2
- The numerator becomes 5(4 − √2) = 20 − 5√2
- The denominator is a difference of two squares: 4² − (√2)² = 16 − 2 = 14
- The result is (20 − 5√2) / 14
- The denominator now contains no root, which is the check that the work is finished
Exam tip
The word "surd" appears on only 2 of the 43 papers, but "exact" appears on 27 of them — that instruction is the real signal, and a decimal scores nothing where an exact value was asked for. Take out the largest square factor: 2√12 is not fully simplified.
Worked example
Rationalising two denominators
Rationalise the denominator of 6/√3, and of 5/(2 + √3).
Solution:
- For a single root, multiply top and bottom by that root
- 6/√3 × √3/√3 = 6√3/3
- Cancel: 2√3
- For a two-term denominator, multiply by the same expression with the middle sign changed
- 5/(2 + √3) × (2 − √3)/(2 − √3)
- The denominator becomes (2 + √3)(2 − √3) = 4 − 2√3 + 2√3 − 3 = 4 − 3 = 1
- The two middle terms always cancel, which is the whole point of changing the sign
- The numerator is 5(2 − √3) = 10 − 5√3
- The answer is 10 − 5√3, over a denominator of 1