0580
Simultaneous Equations
Algebra and Sequences
From a described situation
- Introduce a letter for each unknown and state precisely what each represents, including units
- Each separate fact in the question becomes one equation
- Solve, then answer in context rather than leaving the letters bare
Exam tip
Multiply every term when scaling an equation, the constant included, and show the scaled pair before eliminating — that step carries a method mark. Decide between adding and subtracting from the signs of the matched coefficients. Substitute your answers into the equation you did not use: it catches an error in one line.
Worked example
Forming and solving from a context
Two coffees and three teas cost £11.40. Four coffees and one tea cost £13.80. Find the cost of each drink.
Solution:
- Let c be the cost of a coffee and t the cost of a tea, both in pounds
- The two facts give 2c + 3t = 11.40 and 4c + t = 13.80
- Rearrange the second: t = 13.80 − 4c
- Substitute into the first: 2c + 3(13.80 − 4c) = 11.40
- Expand: 2c + 41.40 − 12c = 11.40, so −10c = −30 and c = 3.00
- Then t = 13.80 − 12.00 = 1.80
- A coffee costs £3.00 and a tea costs £1.80
- Check: 2(3.00) + 3(1.80) = 11.40