0580
Quadratic Equations
Algebra and Sequences
Undoing the square
- To solve, complete the square, isolate the squared bracket, then square root both signs
- Writing ± at the square root stage is what produces the two solutions; forgetting it loses one of them
- Finish by dealing with the number inside the bracket, which shifts both solutions equally
- Leave the squared bracket intact once you have it, because multiplying it out again undoes the work
- When there is a number in front of x², and only when the equation equals zero, you may divide every term by it first
Worked example
Solving and leaving the answer exact
Solve x² − 10x + 4 = 0, giving your answers in exact form.
Solution:
- "Exact" rules out a decimal, so the answer will contain a surd and completing the square gives it directly
- The coefficient of x² is already 1, so no factor needs taking out
- Halve the coefficient of x: half of −10 is −5, so the bracket is (x − 5)²
- (x − 5)² expands to x² − 10x + 25, which is 25 too many, so x² − 10x = (x − 5)² − 25
- The equation becomes (x − 5)² − 25 + 4 = 0
- Collect the constants: (x − 5)² − 21 = 0
- Add 21 to both sides to isolate the square: (x − 5)² = 21
- Take the square root of both sides, keeping both signs, since two numbers square to 21
- x − 5 = ±√21
- Add 5: x = 5 + √21 or x = 5 − √21
- Leave the surd as it stands — writing 9.58 and 0.417 beside it risks losing the mark, because a decimal is not exact