0580
Prime Factors, HCF and LCM
Number
Building a factor tree
- Split the number into any factor pair, then split each factor again
- Continue down every branch until only primes remain, circling each prime as it appears
- Dividing repeatedly by the smallest prime that fits produces a prime at every stage and keeps the tree tidy

- Splitting by a convenient number such as 10 is equally valid, but non-prime results must then be split further

- The circled primes are the same whichever pairs were chosen

Writing the answer
- Multiply the circled primes together, writing them in ascending order
- 252 = 2 × 2 × 3 × 3 × 7
- Collect repeated primes into index form, which is the form questions normally require
- 252 = 2² × 3² × 7
Exam tip
Give the answer in index form with the primes in ascending order, such as 2² × 3² × 7, and leave the factor tree on the page beside it — that is where the method mark sits when the final line slips. Check every circled value really has exactly two factors before multiplying out.
Worked example
A number as a product of its prime factors
Write 360 as a product of its prime factors, in index form.
Solution:
- Split 360 into any two factors and keep splitting until every branch ends on a prime
- 360 = 36 × 10
- 36 = 6 × 6, and each 6 = 2 × 3
- 10 = 2 × 5
- The primes at the ends of the branches are 2, 3, 2, 3, 2, 5
- Collect them in ascending order: 2 × 2 × 2 × 3 × 3 × 5
- In index form, 360 = 2³ × 3² × 5
- Check by multiplying back: 8 × 9 × 5 = 360
- Starting from a different split, such as 360 = 4 × 90, gives the same answer — the tree's shape does not matter