Mathematics (Core)Exam code: 0580
Area and Perimeter
Lengths, Areas and Volumes
The four shapes
- Area is the space inside a shape, measured in squared units such as mm², cm² or m²
| Shape | Area |
|---|---|
| Rectangle | length × width |
| Triangle | ½ × base × perpendicular height |
| Parallelogram | base × perpendicular height |
| Trapezium | ½ × (sum of the parallel sides) × distance between them |
- Only the triangle formula is printed in the paper, so the other three have to be known
- Every one of them uses the perpendicular height, measured at right angles to the base (up to the opposite corner of a triangle, or across to the opposite parallel side) rather than along a sloping side

- The trapezium formula needs the two parallel sides identified first, since the other two play no part
- If a formula escapes you, cut the shape into a rectangle plus one or two triangles instead and add those areas: the total is the same
Worked example
Three areas from the formulas
Find the area of each shape.



Solution:
- The triangle is right-angled, so the two sides meeting at the right angle are the base and the perpendicular height
- Triangle: ½ × 8 × 7 = 28 cm²
- On the parallelogram the 12 cm is the perpendicular height, not the sloping side
- Parallelogram: 15 × 12 = 180 cm²
- On the trapezium the parallel sides are 15 cm and 30 cm, and they are 20 cm apart
- Trapezium: ½ × (15 + 30) × 20 = ½ × 45 × 20 = 450 cm²
- Every answer is in cm² because area is measured in squared units
Areas on a grid
- Count the whole squares inside the shape first, marking them off as you go
- Then pair up the part-squares round the edge to make whole ones
- Check what one square stands for: on a 1 cm² grid the count is the area in cm², and if a square stands for any other area, multiply the count by that area
Worked example
Areas on a 1 cm² grid
(a) The triangle on the first 1 cm² grid has its corners at (1, 1), (7, 1) and (3, 5). Find its area.
(b) Estimate the area of the shape with a curved side on the second 1 cm² grid.
Solution:
- (a) The side from (1, 1) to (7, 1) lies along a grid line, so it makes a good base: 7 − 1 = 6 cm
- The perpendicular height runs straight up from that base to the corner at (3, 5): 5 − 1 = 4 cm
- Area = ½ × 6 × 4 = 12 cm²
- With its corners on grid points the formula is exact, which is quicker and safer than counting the cut squares along the two sloping sides
- (b) A curved side has no formula, so count instead: 13 squares lie wholly inside the shape
- The curved side cuts through 10 more squares; these are roughly half covered each, so together they make about 10 ÷ 2 = 5 whole squares
- Estimated area = 13 + 5 = 18 cm²
- The part squares are only roughly halves, so this is an estimate, and a value a square or so either way is just as reasonable