Real Life Graphs

Mathematics revision notes · Cambridge (CIE) · 0580

1. Conversion graphs

Reading a value off

  • Two quantities that are linked by a fixed rule can be plotted as one straight line, and that line is a conversion graph: either quantity can be found from the other
  • Typical pairs are kilometres and miles, litres and gallons, one currency and another, or a charge against the amount used
  • To convert, start on the axis holding the value you have, go across or up to the line, then turn and read the other axis
A conversion graph of cost in pounds against mass in kilograms, a straight line through the origin, used in both directions: an arrow up from 20 kg then left to £12, and an arrow left from £30 then down to 50 kg
Source: Conversion graphs by Save My Exams
  • Draw those two lines on the graph in pencil, because the examiner credits the reading and the working shows where it came from
A price-against-hours graph with a red line drawn across from £320 on the vertical axis to the line, then straight down to the horizontal axis to read off about 4.6 hours
Source: Conversion graphs by Save My Exams
  • Read the scale on each axis before anything else, since one square is very often not one unit

Graphs through the origin, and graphs that are not

  • A line through the origin means the two quantities are in direct proportion, so values can be scaled up
    • If 80 km reads as 50 miles, then 240 km is three times as far, giving 150 miles
  • A line that starts part way up the vertical axis has a fixed amount built in, and scaling then fails
    • A taxi charging £3 before it moves plus £2 for each mile starts at £3 and reaches £13 after 5 miles
A price-against-hours graph whose line meets the vertical axis at about £45 rather than at the origin, so there is a fixed charge before any hours are counted and values cannot simply be scaled up
Source: Conversion graphs by Save My Exams
  • That starting value is the fixed charge, read where the line meets the vertical axis
  • To convert a value beyond the printed grid on such a graph, find the equation of the line instead of scaling

Worked example

Reading a conversion graph both ways

The graph converts between degrees Celsius and degrees Fahrenheit. Use it to convert 100 °F into °C, and 60 °C into °F.

A conversion graph with degrees Celsius from 0 to 100 along the bottom and degrees Fahrenheit from 0 to 250 up the side, on a grid with small squares of 2 °C by 10 °F, crossed by a straight line from (0, 32) to (100, 212); no readings are drawn

Solution:

  • For 100 °F, start on the vertical axis because Fahrenheit is the quantity given
  • Go across from 100 until the line is reached, then straight down to the Celsius axis
  • The reading is a little under 38, so 100 °F is about 37.5 °C
  • For 60 °C, start on the horizontal axis this time
  • Go up from 60 until the line is reached, then straight across to the Fahrenheit axis
  • The reading is 140 °F
  • The line does not pass through the origin: at 0 °C it is already at 32 °F, so these two scales cannot be converted by multiplying alone

2. Travel graphs

What the picture shows

  • A travel graph puts distance on the vertical axis and time on the horizontal one, so the line traces a journey
  • The vertical axis usually reads "distance from" a named place, so it shows position rather than distance covered
  • A sloping line means movement, and the steeper it is the faster the journey
  • A line sloping up leads away from the starting place; one sloping down comes back towards it
  • A horizontal line means the distance is not changing, so the traveller has stopped
  • Times along the bottom are usually written in 24-hour clock form
A distance-from-home against time graph running from 1 pm to 4 pm: a gentle climb to 2 km, a short horizontal stretch where the traveller has stopped, a steeper climb to 8 km, another flat section, then a steep fall back to 0 km at 4 pm
Source: Distance-time graphs by Save My Exams

Speed from the graph

  • The gradient of a sloping section is the speed of that section
  • Speed is the distance covered divided by the time taken, so read both from the grid and divide
  • Take the units from the axes: kilometres against hours gives km/h, metres against seconds gives m/s
  • Convert a time read in minutes to hours before dividing, or the speed comes out sixty times too small
  • The average speed for a whole journey is the total distance divided by the total time, and the total time includes every stop

Worked example

A there-and-back journey

A cyclist leaves home at 09 00 and rides 24 km to a village, arriving at 10 30. She rests for 30 minutes, then returns home, arriving at 12 30. Find her speed on the outward ride and her average speed for the journey as a whole.

A travel graph with distance from home in km, 0 to 24, up the side and time from 09 00 to 13 00 along the bottom: a straight line rises from 0 at 09 00 to 24 km at 10 30, stays level at 24 km until 11 00, then falls back to 0 at 12 30

Solution:

  • The outward ride runs from 09 00 to 10 30, which is 1.5 hours
  • Speed out = 24 ÷ 1.5 = 16 km/h
  • The rest lasts from 10 30 to 11 00, drawn as a horizontal line
  • The return runs from 11 00 to 12 30, also 1.5 hours, so the return speed is also 16 km/h
  • For the average speed, the total distance is 24 + 24 = 48 km
  • The total time is 09 00 to 12 30, which is 3.5 hours, including the rest
  • Average speed = 48 ÷ 3.5 = 13.714…, which is 13.7 km/h to 3 significant figures
  • To add a journey to a printed travel graph, work out where it starts and where it ends, mark both points, and join them with a ruled line

3. Gradient as a rate of change

What the number means

  • On any graph of one quantity against another, the gradient says how much the vertical quantity changes for each unit of the horizontal one
  • The units of that rate are the units up the side divided by the units along the bottom
    • Litres against minutes gives litres per minute
    • Dollars against hours gives dollars per hour
  • A straight line means the rate never changes; a horizontal line means the quantity is not changing at all
  • A negative gradient means the vertical quantity is falling as the horizontal one increases
    • A graph of fuel in a tank against distance driven has a negative gradient, and its size is the fuel used per kilometre
  • A question asking what the gradient represents wants the quantity named with its units, not just a number

Worked example

Saying what a gradient means

A tank is being emptied. The graph of the volume of water V litres against the time t minutes is a straight line through (0, 300) and (25, 50). Find the gradient and say what it represents.

A straight-line graph of volume V litres, 0 to 300, against time t minutes, 0 to 30, falling from 300 at t = 0 to 0 at t = 30, with dots at (0, 300) and (25, 50)

Solution:

  • Gradient = change up the side ÷ change along the bottom
  • Change in volume = 50 − 300 = −250 litres
  • Change in time = 25 − 0 = 25 minutes
  • Gradient = −250 ÷ 25 = −10
  • The units are litres per minute, taken from the two axes
  • The gradient is negative because the volume is falling, so it represents the tank emptying at 10 litres per minute
  • Naming the quantity and its units is what the question asks for; the bare number −10 is not an answer to "what does the gradient represent"
A straight line y = mx + c with a right-angled triangle marked on it labelled change in x along the bottom and change in y up the side, and the reminder that on a straight line the gradient, change in y divided by change in x, is the same everywhere
Source: Rates of change of graphs by Save My Exams

4. Speed-time graphs

Reading motion off the graph

  • A speed–time graph puts speed on the vertical axis and time on the horizontal one, so it looks similar to a travel graph but says something quite different
  • Check the vertical axis label first, because reading one as the other makes every answer wrong
  • Here the gradient is the acceleration, found as the change in speed divided by the time taken
  • The units are the speed units divided by the time units, so metres per second against seconds gives m/s²
  • A line sloping up is speeding up, and a line sloping down is slowing down, which is called deceleration
  • A horizontal line means constant speed, and a horizontal line at zero means the object is at rest
  • A straight sloping line means the acceleration is constant, while a curve means it is changing
A curve rising ever more steeply with tangents drawn at two points A and B, each with its own dashed right-angled triangle: the triangle at B is much steeper than the one at A, so the rate of change is greater there
Source: Rates of change of graphs by Save My Exams

Distance from the area

  • The distance travelled is the area between the graph and the time axis
  • On this specification the area you are asked for lies under straight sections of the graph only, so it splits into rectangles, triangles and trapeziums
  • Work out each piece separately and add them, or treat the whole shape as one trapezium where that fits
  • Check the units before writing the answer down, since a question may want the distance in kilometres when the axes are in metres and seconds

Worked example

Acceleration and distance from a speed–time graph

The graph shows the first 20 seconds of a car journey. Find the acceleration over the first 6 seconds, and the total distance travelled.

A speed-time graph with speed in metres per second up the side and time in seconds along the bottom: the line rises steadily from the origin to 9 m/s at 6 seconds, stays level at 9 m/s until 15 seconds, then falls steadily to zero at 20 seconds
Source: Speed-time graphs by Save My Exams

Solution:

  • Over the first 6 seconds the speed rises from 0 to 9 m/s
  • Acceleration = change in speed ÷ time = 9 ÷ 6 = 1.5 m/s²
  • For the distance, find the area between the line and the time axis, splitting it into three pieces
  • The first piece is a triangle: ½ × 6 × 9 = 27 m
  • The middle piece is a rectangle: (15 − 6) × 9 = 9 × 9 = 81 m
  • The last piece is a triangle: ½ × (20 − 15) × 9 = ½ × 5 × 9 = 22.5 m
  • Total distance = 27 + 81 + 22.5 = 130.5 m
  • The whole shape is a trapezium, so it can be done in one step as a check: ½ × (20 + 9) × 9 = 130.5 m

5. Curved graphs and changing rates

When the rate itself changes

  • On a curve the steepness keeps changing, so the rate of change differs from point to point and one gradient cannot describe it
  • To find the rate at one moment, draw a tangent at that point and work out its gradient, exactly as in the further graphs topic
  • On a travel graph a tangent gives the speed at that instant; on a speed–time graph it gives the acceleration
  • A curve getting steeper means the rate is increasing, and a curve flattening out means it is decreasing

Matching a graph to a situation

  • A question can show a container being filled at a steady rate and ask which depth-against-time graph fits it
  • Reason from the width of the container, since a steady inflow raises the level faster where the container is narrower
    • Straight sides give a straight line, because the depth rises at one steady rate
    • A container narrowing towards the top gives a curve that steepens
    • A container widening towards the top gives a curve that flattens
  • The same reasoning matches any pair of quantities, so read the axis labels and ask what one unit of the horizontal quantity does to the vertical one

Worked example

Matching each container to its graph

Each graph shows the depth of water, d cm, in one of the containers as it is filled from a tap running at a constant rate. Match each graph to its container.

Four containers labelled A to D above four depth-against-time graphs numbered 1 to 4. A is a triangular prism standing on its base so it narrows towards the top, B is a container with sloping sides that widens towards the top, C is a round flask that is narrow at the bottom, wide in the middle and narrow again at the neck, and D is a cuboid with vertical sides. Graph 1 is a straight line, graph 2 curves upwards getting steeper, graph 3 rises steeply then flattens, and graph 4 is steep, then shallow, then steep again
Source: Rates of change of graphs by Save My Exams

Solution:

  • The water goes in at a steady rate, so the depth rises fastest where the container is narrowest
  • Graph 1 is straight, so the depth rises at one steady rate all the way up, which needs a container of constant width
  • Graph 1 is container D, the cuboid with vertical sides
  • Graph 2 starts shallow and steepens, so the depth rises faster and faster, which needs a container narrowing towards the top
  • Graph 2 is container A
  • Graph 3 starts steep and flattens, so the depth rises more and more slowly, which needs a container widening towards the top
  • Graph 3 is container B
  • Graph 4 is steep, then shallow, then steep again, which matches narrow, then wide, then narrow
  • Graph 4 is container C, the round flask
  • Read the shape of each curve first and describe it in words before looking at the containers, because the reasoning is the same every time