Mathematics (Core)Exam code: 0580

Rounding Estimation and Bounds

Number

Making the estimate

  • Rounding every value to one significant figure turns an awkward calculation into one that can be done mentally
    • 19.4 becomes 20 and 4.7 becomes 5
  • When the question says 1 significant figure, round to exactly that, even where another rounding would make the arithmetic simpler
  • Never round a value to zero: a zero denominator makes the calculation undefined, and a zero numerator destroys the estimate

Deciding whether the estimate is too big or too small

  • For a sum or a product, rounding both values the same way settles it
OperationBoth rounded upBoth rounded down
a + bOverestimateUnderestimate
a × bOverestimateUnderestimate
  • For a difference or a quotient the second value works in the opposite direction
Operationa up, b downa down, b up
a − bOverestimateUnderestimate
a ÷ bOverestimateUnderestimate
  • Where the two roundings pull opposite ways, the direction cannot be decided without more care

Exam tip

Write every number at 1 significant figure

Set in 7 of the 22 papers, all on Paper 1, for two marks: one for the calculation rewritten with every number at 1 significant figure, one for its value. A single number left with more figures, even 4.0 written for 3.87, costs both and leaves one special-case mark at most. So for 58.3 × 0.214 ÷ 3.87, write 60 × 0.2 ÷ 4 on its own line and give its value, 3, as the estimate.

Worked example

Estimating and judging the direction

Estimate the value of 19.4 × 4.7, and state whether the estimate is too large or too small.

Solution:

  • Round each value to one significant figure: 19.4 becomes 20 and 4.7 becomes 5
  • Multiply the rounded values: 20 × 5 = 100
  • The estimate is 100
  • Both values were rounded up, and this is a product, so the estimate is an overestimate
  • The exact value is 91.18, which confirms the direction

Build on this topic