Circles, Arcs and Sectors

Mathematics revision notes · Cambridge (CIE) · 0580

1. Circumference and area

The two formulas

  • The distance round a circle is its circumference, and the space inside is its area
  • Both formulas are printed in the List of formulas at the front of the paper
    • Area: A = πr²
    • Circumference: C = 2πr, which is the same as C = πd because the diameter is twice the radius
  • Read the diagram carefully to see whether the number given is the radius or the diameter, since halving or doubling at the wrong moment is the usual error
A circle with a radius r and a diameter d both marked as dashed lines, beside the two formulas: area equals pi r squared, and circumference equals pi d, which is the same as 2 pi r
Source: Area & Circumference by Save My Exams
  • Area needs the radius squared, so a diameter must be halved first
  • Circumference is a length and takes units such as cm; area is a space and takes squared units such as cm²

Answers in terms of π

  • Questions frequently ask for the answer "in terms of π", which means leaving π in the answer rather than multiplying it out
  • Work in exact numbers throughout and collect the π at the end, so a circle of radius 5 has area 25π cm² and circumference 10π cm
  • "In its simplest form" alongside it means the number in front of π should be fully simplified
  • Only round when the question actually asks for a decimal, and then to whatever accuracy it states

Exam tip

Stop at the answer in terms of π

When a question asks only for the answer in terms of π, the final mark is for that form. The schemes give only the method marks for a decimal answer, even when the working is right, and that includes a value found with 3.14 or 22/7 in place of π. Write the answer with π in it on the answer line and leave it there.

Worked example

Circumference and area of a circle

A circle has radius 11 cm. Find its circumference and its area, in terms of π and then to 3 significant figures.

Solution:

  • Circumference = 2πr = 2 × π × 11 = 22π cm
  • To 3 significant figures that is 69.1 cm
  • Area = πr² = π × 11² = π × 121 = 121π cm²
  • To 3 significant figures that is 380 cm²
  • Square the radius before multiplying by π: (π × 11)² would be a different number entirely
  • The circumference is a length, so its units are cm; the area is in cm²

2. Arcs and sectors

The vocabulary

  • An arc is part of the circumference, and a sector is the slice enclosed by two radii and an arc
  • Two points on a circle cut it into a shorter minor arc and a longer major arc, and two radii likewise cut it into a minor and a major sector
  • The angle at the centre between the two radii is usually labelled θ
  • A question naming the major arc or sector wants the larger piece, so subtract the marked angle from 360° before doing anything else

The two formulas

  • An arc and a sector are simply fractions of the whole circle, and the fraction is θ ÷ 360
  • Arc length = (θ ÷ 360) × 2πr
  • Sector area = (θ ÷ 360) × πr²
  • Neither formula is printed in the paper, so both have to be known, although each is just the circle formula scaled by the fraction
A sector drawn with radius r and the angle theta marked at its point, beside the two formulas it needs: sector area equals theta over 360 times pi r squared, and arc length equals theta over 360 times 2 pi r
Source: Arc Lengths & Sector Areas by Save My Exams
  • θ can be any angle, and the syllabus explicitly includes major sectors, where θ is bigger than 180°
  • To go all the way round a sector you travel along the arc and back down both radii, so its perimeter includes those two straight edges — routinely forgotten

Worked example

Arc, area and perimeter of a sector

A sector of a circle has radius 12 cm and sector angle 45°. Find its arc length, its area, and its perimeter. Give the first two in terms of π.

A sector of a circle with centre O marked at its point. The two straight radii are drawn, one of them labelled 12 cm, and the angle between them at O is marked 45 degrees. Neither the arc length nor the area is shown.

Solution:

  • The fraction of the circle is 45 ÷ 360 = 1/8
  • The full circumference is 2π × 12 = 24π cm
  • Arc length = 1/8 × 24π = 3π cm
  • The full area is π × 12² = 144π cm²
  • Sector area = 1/8 × 144π = 18π cm²
  • The perimeter is the arc plus both radii: 3π + 12 + 12
  • Perimeter = (3π + 24) cm

Worked example

A major sector

A sector of a circle, centre O, has radius 10 cm. The minor sector angle is 72°. Find the area of the major sector and the length of the major arc, in terms of π.

A circle with centre O and two radii drawn, one labelled 10 cm. The angle between them is marked 72 degrees and the smaller wedge it cuts off is left white, while the whole of the rest of the circle, the major sector, is shaded grey. The 288 degree angle is not marked.

Solution:

  • The major sector is the rest of the circle, so its angle is 360 − 72 = 288°
  • The fraction is 288 ÷ 360 = 4/5
  • The full area is π × 10² = 100π cm²
  • Major sector area = 4/5 × 100π = 80π cm²
  • The full circumference is 2π × 10 = 20π cm
  • Major arc = 4/5 × 20π = 16π cm
  • Check: the minor sector would be 1/5 of the circle, and 80π + 20π = 100π

3. Semicircles and compound shapes

Parts of circles

  • A semicircle is half a circle, so work out the whole circle's area and take half of it
  • Its perimeter is not half the circumference: it is the curved half plus the straight diameter across the bottom
    • A semicircle of radius 6 cm has area 18π cm² and perimeter (6π + 12) cm
A semicircle standing on its straight edge, with the centre marked on that edge and the full 16 cm width labelled as the diameter across the bottom
Source: Area & Circumference by Save My Exams
  • A quarter circle works the same way, with two radii forming the straight edges
  • Whenever a shape has a curved edge and a straight one, list the pieces of the perimeter before adding, so none is left out

Shapes built from circles

  • Compound shapes combine circles or parts of circles with rectangles and triangles
  • Add the pieces where the shape is built up, and subtract where a piece has been removed
  • A shaded region between two circles with the same centre is the larger area minus the smaller
  • Sketch the split and label each piece, since the separate areas carry the method marks
  • Keep every part in terms of π until the end, which makes the final collecting much easier

Worked example

A semicircle's area and perimeter

A semicircle has diameter 12 cm. Find its area and its perimeter, in terms of π.

Solution:

  • The radius is half the diameter, so r = 6 cm
  • For the area, find the whole circle's area and halve it
  • Whole circle: π × 6² = 36π
  • Area of the semicircle = 36π ÷ 2 = 18π cm²
  • The perimeter is not half the circumference: the straight edge counts too
  • Curved part = half of 2π × 6 = 6π
  • Straight part = the diameter = 12
  • Perimeter = (6π + 12) cm
  • Stopping at 6π is the standard error: it leaves out the 12 cm straight edge